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Second solution in Clear category for Pawn Brotherhood by artemrudenko
def safe_pawns(pawns):
candidates = lambda pwn: ["{}{}".format(chr(ord(pwn[0])+1), int(pwn[1])-1),
"{}{}".format(chr(ord(pwn[0])-1), int(pwn[1])-1)]
return sum(1 for pawn in pawns if any(cnd_ in pawns for cnd_ in candidates(pawn)))
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert safe_pawns({"b4", "d4", "f4", "c3", "e3", "g5", "d2"}) == 6
assert safe_pawns({"b4", "c4", "d4", "e4", "f4", "g4", "e5"}) == 1
Sept. 3, 2014
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