First clear solution for Pawn Brotherhood by _ukasz_Mas_owski - python coding challenges

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First solution in Clear category for Pawn Brotherhood by _ukasz_Mas_owski

def safe_pawns(pawns):
    
    iBezp = 0
    ile = 0

    index_pionkow = set()
    for p in pawns:
        wier = int(p[1]) - 1
        kol = ord(p[0]) - 97
        index_pionkow.add((wier, kol))
        
    for wier, kol in index_pionkow:
        iBezp = ((wier - 1, kol - 1) in index_pionkow) or ((wier - 1, kol + 1) in index_pionkow)
        if iBezp:
            ile+=1

    return ile

if __name__ == '__main__':
    #These "asserts" using only for self-checking and not necessary for auto-testing
    assert safe_pawns({"b4", "d4", "f4", "c3", "e3", "g5", "d2"}) == 6
    assert safe_pawns({"b4", "c4", "d4", "e4", "f4", "g4", "e5"}) == 1

Nov. 7, 2016

Look up in the Dict()

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