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ord(), chr() and if statements solution in Clear category for Pawn Brotherhood by Splitter
def safe_pawns(pawns):
count = 0
for pawn in pawns:
if pawn[0] == 'a':
if f'b{int(pawn[1]) - 1}' in pawns:
count += 1
elif pawn[0] == 'h':
if f'g{int(pawn[1]) - 1}' in pawns:
count += 1
elif chr(ord(pawn[0]) - 1) + str(int(pawn[1]) - 1) in pawns or \
chr(ord(pawn[0]) + 1) + str(int(pawn[1]) - 1) in pawns:
count += 1
return count
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert safe_pawns({"b4", "d4", "f4", "c3", "e3", "g5", "d2"}) == 6
assert safe_pawns({"b4", "c4", "d4", "e4", "f4", "g4", "e5"}) == 1
print("Coding complete? Click 'Check' to review your tests and earn cool rewards!")
July 12, 2019
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