Clear and simple (ASCII convertion used) clear solution for Pawn Brotherhood by Sebastian.M - python coding challenges

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Clear and simple (ASCII convertion used) solution in Clear category for Pawn Brotherhood by Sebastian.M

def safe_pawns(pawns):
    safePawns = 0
    for x in pawns:
        covered = False
        column = x[0]
        row = x[1]
        for y in pawns:
            if(x != y and int(row) == int(y[1])+1 and (ord(column) == ord(y[0])+1 or ord(column) == ord(y[0])-1)):
                covered = True
        if(covered):
            safePawns+=1    
    return safePawns

if __name__ == '__main__':
    #These "asserts" using only for self-checking and not necessary for auto-testing
    assert safe_pawns({"b4", "d4", "f4", "c3", "e3", "g5", "d2"}) == 6
    assert safe_pawns({"b4", "c4", "d4", "e4", "f4", "g4", "e5"}) == 1

Oct. 7, 2016

Comments:

thiryj on Oct. 11, 2016, 1:01 a.m.
<p>Line 8: "x != y" is not needed. That condition will never be true at the same time as your tests for covered.</p>

Look up in the Dict()

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