Pawn Brotherhood - 2 clear solution for Pawn Brotherhood by KacperBeisert - python coding challenges

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Pawn Brotherhood - 2 solution in Clear category for Pawn Brotherhood by KacperBeisert

def safe_pawns(pawns):
    
    count = 0
    for item in pawns:
        if (chr(ord(item[0])-1) + str(int(item[1])-1)) in pawns: 
            count += 1
        elif (chr(ord(item[0])+1) + str(int(item[1])-1)) in pawns: 
            count += 1
    return count



if __name__ == '__main__':
    #These "asserts" using only for self-checking and not necessary for auto-testing
    assert safe_pawns({"b4", "d4", "f4", "c3", "e3", "g5", "d2"}) == 6
    assert safe_pawns({"b4", "c4", "d4", "e4", "f4", "g4", "e5"}) == 1

Dec. 14, 2015

Look up in the Dict()

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