First clear solution for Pawn Brotherhood by H0r4c3 - python coding challenges

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First solution in Clear category for Pawn Brotherhood by H0r4c3

def safe_pawns(pawns: set) -> int:
    counter = 0
    for item in pawns:
        guardian1 = str(chr((ord(item[0]) - 1))) + str(int(item[1]) - 1)
        guardian2 = str(chr((ord(item[0]) + 1))) + str(int(item[1]) - 1)
        if (guardian1 in pawns) or (guardian2 in pawns):
            counter += 1
        else:
            continue
   
    return counter

if __name__ == '__main__':
    #These "asserts" using only for self-checking and not necessary for auto-testing
    assert safe_pawns({"b4", "d4", "f4", "c3", "e3", "g5", "d2"}) == 6
    assert safe_pawns({"b4", "c4", "d4", "e4", "f4", "g4", "e5"}) == 1
    print("Coding complete? Click 'Check' to review your tests and earn cool rewards!")

Nov. 13, 2021

Comments:

ozg on Aug. 13, 2022, 11:25 p.m.
<p>I think str(chr(ord(item[0]) - 1))) is not easy to read.</p>

H0r4c3 on Aug. 14, 2022, 6:45 a.m.
<p>Yes, you are right, it is difficult to read it.</p>

Look up in the Dict()

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