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Clear? solution in Clear category for Pawn Brotherhood by EcNeu
def safe_pawns(pawns):
safe = 0
for pawn in pawns:
diagonal_left = chr(ord(pawn[0]) - 1) + str(int(pawn[1]) - 1)
diagonal_right = chr(ord(pawn[0]) + 1) + str(int(pawn[1]) - 1)
if diagonal_left in pawns or diagonal_right in pawns:
safe += 1
return safe
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert safe_pawns({"b4", "d4", "f4", "c3", "e3", "g5", "d2"}) == 6
assert safe_pawns({"b4", "c4", "d4", "e4", "f4", "g4", "e5"}) == 1
April 25, 2015
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