First creative solution for Pawn Brotherhood by -ninth- - python coding challenges

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First solution in Creative category for Pawn Brotherhood by -ninth-

def safe_pawns(pawns):
    x="abcdefgh"
    y="12345678"
    s = 0
    for i in pawns:
        if i[1] != "1":
            if i[0]!='a' and x[x.index(i[0]) -1] + y[y.index(i[1]) -1] in pawns or i[0]!='h' and x[x.index(i[0]) +1] + y[y.index(i[1]) -1] in pawns:
                s+=1
    return s

Aug. 13, 2017

Comments:

gileadslostson on Aug. 3, 2018, 7:45 a.m.
<p>I like this =) Not the most readable but then creative rarely is!</p>

Look up in the Dict()

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