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First solution in Clear category for Pangram by wojtek96
def check_pangram(text):
text = text.lower()
tab=[]
tab_a=[]
for i in text:
if i.islower and ord(i) > 96 and ord(i) < 123 :
if i not in tab_a:
tab_a.append(i)
tab.append(ord(i))
if len(tab_a) == 26:
return True
else:
return False
if __name__ == '__main__':
# These "asserts" using only for self-checking and not necessary for auto-testing
assert check_pangram("The quick brown fox jumps over the lazy dog."), "brown fox"
assert not check_pangram("ABCDEF"), "ABC"
assert check_pangram("Bored? Craving a pub quiz fix? Why, just come to the Royal Oak!"), "Bored?"
Dec. 15, 2016
