First clear solution for Pangram by sesenion - python coding challenges

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First solution in Clear category for Pangram by sesenion

def check_pangram(text: str) -> bool:
    alphabet = set("abcdefghijklmnopqrstuvwxyz")
    chars_in_text = set(text.lower())
    return len(alphabet - chars_in_text) == 0


print("Example:")
print(check_pangram("The quick brown fox jumps over the lazy dog."))

# These "asserts" are used for self-checking
assert check_pangram("The quick brown fox jumps over the lazy dog.") == True
assert check_pangram("ABCDEF") == False
assert check_pangram("abcdefghijklmnopqrstuvwxyz") == True
assert check_pangram("ABCDEFGHIJKLMNOPQRSTUVWXYZ") == True
assert check_pangram("abcdefghijklmnopqrstuvwxy") == False
assert (
    check_pangram("Bored? Craving a pub quiz fix? Why, just come to the Royal Oak!")
    == True
)
assert check_pangram("As quirky joke, chefs won't pay devil magic zebra tax.") == True
assert check_pangram("Six big devils from Japan quickly forgot how to walt.") == False

print("The mission is done! Click 'Check Solution' to earn rewards!")

Nov. 19, 2022

Comments:

BootzenKatzen on April 10, 2023, 9:35 p.m.
<p>Oh nice! I didn't think of using sets! That's clever. It removes all the duplicate letters from the lowercase text and then checks to see if the alphabet is the same length. Just curious, what part of this deals with the punctuation? Is it the lower() or the set()?</p>

sesenion on April 11, 2023, 2 a.m.
<p>It's the "-" between the sets. It removes everything from set1 that is part of set2. The punctuation is still part of set2, but doesn't matter. The lower() is used to make the function case insensitive.</p>

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