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First solution in Clear category for Pangram by hbczmxy
from string import ascii_lowercase
def check_pangram(text):
'''
is the given text is a pangram.
'''
# Use each letter as the key of the dictionary, and set zero as the default value
lower_case = dict.fromkeys(ascii_lowercase, 0)
# Each time a letter is detected, its corresponding value is increased by one
for char in text.lower():
if char in ascii_lowercase:
lower_case[char] += 1
# Check whether the values corresponding to all the keys are no longer zero
return all(lower_case[char] != 0 for char in lower_case)
if __name__ == '__main__':
# These "asserts" using only for self-checking and not necessary for auto-testing
assert check_pangram("The quick brown fox jumps over the lazy dog."), "brown fox"
assert not check_pangram("ABCDEF"), "ABC"
assert check_pangram("Bored? Craving a pub quiz fix? Why, just come to the Royal Oak!"), "Bored?"
print('If it is done - it is Done. Go Check is NOW!')
Dec. 10, 2021
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