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one row solution in Clear category for Pangram by chukkloon
def check_pangram(text):
return True if len(set([i.lower() for i in text if 97 <= ord(i.lower()) <= 122])) == 26 else False
if __name__ == '__main__':
# These "asserts" using only for self-checking and not necessary for auto-testing
assert check_pangram("The quick brown fox jumps over the lazy dog."), "brown fox"
assert not check_pangram("ABCDEF"), "ABC"
assert check_pangram("Bored? Craving a pub quiz fix? Why, just come to the Royal Oak!"), "Bored?"
Nov. 11, 2016
