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First solution in Clear category for Pangram by _ukasz_Mas_owski
DICTIONARY = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
def check_pangram(text):
existingLetters = []
result = True
for i in range(len(text)):
if (text[i] in DICTIONARY or text[i].upper() in DICTIONARY) and text[i] not in existingLetters:
existingLetters.append(text[i].upper())
for i in range(len(DICTIONARY)):
if DICTIONARY[i] not in existingLetters:
result = False
break
print(sorted(existingLetters))
print(result)
return result
if __name__ == '__main__':
# These "asserts" using only for self-checking and not necessary for auto-testing
assert check_pangram("The quick brown fox jumps over the lazy dog."), "brown fox"
assert not check_pangram("ABCDEF"), "ABC"
assert check_pangram("Bored? Craving a pub quiz fix? Why, just come to the Royal Oak!"), "Bored?"
Jan. 25, 2017
