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Set generation and length comparison solution in Clear category for Pangram by Rob019
def check_pangram(text):
# Create a set (no repetitions) with all and only letters in given text
# If this set is 26 (char) long then it's a pangram!
return len({x for x in text.lower() if x >= 'a' and x <= 'z'}) == 26
if __name__ == '__main__':
# These "asserts" using only for self-checking and not necessary for auto-testing
assert check_pangram("The quick brown fox jumps over the lazy dog."), "brown fox"
assert not check_pangram("ABCDEF"), "ABC"
assert check_pangram("Bored? Craving a pub quiz fix? Why, just come to the Royal Oak!"), "Bored?"
Feb. 11, 2015
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