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First solution in Clear category for Pangram by Krzysztof_bonczyk
def check_pangram(text):
alist=[]
text=text.lower()
for i in text:
if i not in alist and ord(i)>=ord('a') and ord(i)<=ord('z'):
alist.append(i)
print(alist)
if len(alist)==26:
return 1
else:
return 0
if __name__ == '__main__':
# These "asserts" using only for self-checking and not necessary for auto-testing
assert check_pangram("The quick brown fox jumps over the lazy dog."), "brown fox"
assert not check_pangram("ABCDEF"), "ABC"
assert check_pangram("Bored? Craving a pub quiz fix? Why, just come to the Royal Oak!"), "Bored?"
Nov. 30, 2016
