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First solution in Clear category for Pangram by KrzysztofP
def check_pangram(text):
text=text.lower()
alphabet=["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"]
if len(text)0 and i
Nov. 2, 2016
