Cursion creative solution for On the same path by veky - python coding challenges

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Cursion solution in Creative category for On the same path by veky

C=lambda f,x:any(r==x or C(f,x)for r,f in f)
D=lambda r,f,p,c:C(f,c)if r==p else any(D(r,f,p,c)for r,f in f)
on_same_path=lambda t,s:[D(*t,a,b)or D(*t,b,a)for a,b in s]

Dec. 11, 2019

Comments:

B_dur on June 17, 2020, 1:38 a.m.
Nice short solution!

veky on June 17, 2020, 6:41 a.m.
Of course. But do you understand how it works? :-]

B_dur on June 24, 2020, 9:16 a.m.
It was hard to decrypt this code. I learned a lot from this.

veky on June 24, 2020, 11:18 a.m.
That was the intention. ;-D

Rock

0 %

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