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First solution in Clear category for Number Base by werepire
def checkio(str_number, radix):
alphabet="0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ"
n=0
for i in range(0, len(str_number)):
a=str_number[i]
index=alphabet.find(a)
if(index>=radix):
return -1
n*=radix
n+=index
return n
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("AF", 16) == 175, "Hex"
assert checkio("101", 2) == 5, "Bin"
assert checkio("101", 5) == 26, "5 base"
assert checkio("Z", 36) == 35, "Z base"
assert checkio("AB", 10) == -1, "B > A > 10"
Oct. 25, 2016
