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First solution in Clear category for Number Base by u2ezi
def checkio(str_number, radix):
result=0
pradix=1;
i=len(str_number)-1
while(i>=0):
if ord(str_number[i])>=ord('A'):
if ord(str_number[i])-ord('A')+10>=radix: return -1
result+=(ord(str_number[i])-ord('A')+10)*pradix
else:
if (int)(str_number[i])>=radix: return -1
result+=(int)(str_number[i])*pradix
pradix*=radix
i-=1
return result
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("AF", 16) == 175, "Hex"
assert checkio("101", 2) == 5, "Bin"
assert checkio("101", 5) == 26, "5 base"
assert checkio("Z", 36) == 35, "Z base"
assert checkio("AB", 10) == -1, "B > A > 10"
Oct. 16, 2016
