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isalpha() solution in Clear category for Number Base by marcel.sliwinski
def checkio(str_number, radix):
ans=0
j=0
str_number=str_number[::-1]
for i in str_number:
if i.isalpha():
a=ord(i)-55
else:
a=int(i)
if(a A > 10"
Feb. 23, 2017
