Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
First solution in Clear category for Number Base by karolk10
def checkio(str_number, radix):
wynik = 0
k=0
for i in range(len(str_number)-1,-1,-1):
if str_number[i].isdigit() == True:
num = int(str_number[i])
else:
num = ord(str_number[i]) - 55
print(num)
if(num >= radix):
wynik = -1
if wynik != -1:
wynik = wynik + (num * (radix ** k))
k = k + 1
return wynik
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("AF", 16) == 175, "Hex"
assert checkio("101", 2) == 5, "Bin"
assert checkio("101", 5) == 26, "5 base"
assert checkio("Z", 36) == 35, "Z base"
assert checkio("AB", 10) == -1, "B > A > 10"
Nov. 15, 2016
Comments: