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First solution in Clear category for Number Base by Wojtas1411
def checkio(str_number, radix):
f=0
p=1
k="0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ"
check=True
for i in range(len(str_number)):
if k.rfind(str_number[i])>radix-1:
check=False
if check==False:
return -1
else:
for i in range(len(str_number)-1, -1, -1):
f+=p*k.rfind(str_number[i])
p*=radix
return f
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("AF", 16) == 175, "Hex"
assert checkio("101", 2) == 5, "Bin"
assert checkio("101", 5) == 26, "5 base"
assert checkio("Z", 36) == 35, "Z base"
assert checkio("AB", 10) == -1, "B > A > 10"
Oct. 23, 2016
