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First solution in Clear category for Number Base by PawelMartyniuk
def checkio(str_number, radix):
numerals="0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ"
n = 0
result = 0
#if(int(numerals.index(str_number[len(str_number)-1-n] < radix)
while(n < len(str_number)):
if (int(numerals.index(str_number[len(str_number)-1-n])) < radix):
result = result + int(numerals.index(str_number[len(str_number)-1-n]))* ( radix **n)
else:
return -1
n += 1
return result
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("AF", 16) == 175, "Hex"
assert checkio("101", 2) == 5, "Bin"
assert checkio("101", 5) == 26, "5 base"
assert checkio("Z", 36) == 35, "Z base"
assert checkio("AB", 10) == -1, "B > A > 10"
1001
14731
Oct. 24, 2016
