math.log10 creative solution for Number Length by makoto_yamagata - python coding challenges

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math.log10 solution in Creative category for Number Length by makoto_yamagata

import math


def number_length(a: int) -> int:
    return int(math.log10(a)) + 1 if a else 1

Dec. 24, 2020

Comments:

Calen on March 19, 2021, 11:41 a.m.
interesting

Borzislav on Oct. 31, 2021, 3:05 p.m.
Doesn't math.log10 start giving errors if you have a number with over 15 digits?

ggeasypeasy on Nov. 17, 2021, 12:52 a.m.
Did you try it?

buntpupil on Nov. 30, 2021, 8:30 a.m.
worked fine for me for 40 digits

Borzislav on Dec. 11, 2021, 10:39 p.m.
So, it could be an edge case where the error appears for numbers that start with 15x"9"s and above, however the actual error still appears. So, why not test both? Try entering 16x"9"s and see the results? "9999999999999999" Should be 16, no? Does a function with math.log10 return "16" or "17"? Or try this code: <pre class='brush: python'>import math def number_length_log(a: int) -> int: return int(math.log10(a)) + 1 if a else 1 def number_length(number: int) -> int: return len(str(number)) x = int(input("Example:")) print(number_length(x)) print(number_length_log(x)) </pre>

stoutrl on March 7, 2022, 5:51 p.m.
Like the creative approach.

BlueCat_OAO on Nov. 29, 2023, 7:03 a.m.
nice!

Madalean33 on Nov. 30, 2023, 7:25 p.m.
creative!

Strings and Integers

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