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Second solution in Clear category for Numbers Factory by siebenschlaefer
def checkio(n):
"""Return the smallest number where the product of its digits is 'n'."""
digits = []
for i in range(9, 1, -1):
while n % i == 0:
digits.append(str(i))
n //= i
if n > 1:
return 0
return int("".join(reversed(digits)))
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio(20) == 45, "1st example"
assert checkio(21) == 37, "2nd example"
assert checkio(17) == 0, "3rd example"
assert checkio(33) == 0, "4th example"
assert checkio(3125) == 55555, "5th example"
assert checkio(9973) == 0, "6th example"
July 9, 2015
