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Second solution in Clear category for Numbers Factory by gyahun_dash
def checkio(number):
divisors = []
for divisor in reversed(range(2, 10)):
while number % divisor == 0:
divisors.insert(0, divisor)
number //= divisor
return int(''.join(map(str, divisors))) if number == 1 else 0
May 5, 2015
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