First clear solution for Numbers Factory by freeman_lex - python coding challenges - Py.CheckiO

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First solution in Clear category for Numbers Factory by freeman_lex

def checkio(n):
    s = ''
    for i in range(9, 1, -1):
        while not n % i:
            s = str(i) + s
            n /= i
    return 0 if n > 1 else int(s)

July 2, 2016

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