Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
while for break else break solution in Clear category for Numbers Factory by M157q
def checkio(number):
factors = []
while number > 1:
for i in range(9, 1, -1):
if number % i == 0:
factors.append(i)
number /= i
break
else:
factors.append(0)
break
if 0 not in factors:
return int(''.join(map(str, sorted(factors))))
else:
return 0
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio(20) == 45, "1st example"
assert checkio(21) == 37, "2nd example"
assert checkio(17) == 0, "3rd example"
assert checkio(33) == 0, "4th example"
assert checkio(3125) == 55555, "5th example"
assert checkio(9973) == 0, "6th example"
Nov. 14, 2015
Comments:
