Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
First solution in Clear category for Non-unique Elements by wrak
#Your optional code here
#You can import some modules or create additional functions
def checkio(data):
#Your code here
#It's main function. Don't remove this function
#It's used for auto-testing and must return a result for check.
t=data
p=0
a=len(t)
for x in range(a):
if p==1:
p=0
try:
while p==0:
if t.count(t[x])==1:
t.remove(t[x])
p=0
else:
p=1
except:
break
#replace this for solution
return t
#Some hints
#You can use list.count(element) method for counting.
#Create new list with non-unique elements
#Loop over original list
if __name__ == "__main__":
#These "asserts" using only for self-checking and not necessary for auto-testing
assert list(checkio([1, 2, 3, 1, 3])) == [1, 3, 1, 3], "1st example"
assert list(checkio([1, 2, 3, 4, 5])) == [], "2nd example"
assert list(checkio([5, 5, 5, 5, 5])) == [5, 5, 5, 5, 5], "3rd example"
assert list(checkio([10, 9, 10, 10, 9, 8])) == [10, 9, 10, 10, 9], "4th example"
print("It is all good. Let's check it now")
Oct. 17, 2017
Comments:
