One-liner variation creative solution for Non-unique Elements by suic - python coding challenges

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One-liner variation solution in Creative category for Non-unique Elements by suic

checkio = lambda d: list(filter(lambda i: d.count(i) - 1, d))

Feb. 6, 2015

Comments:

sajkatav on Dec. 16, 2015, 9:39 a.m.
Very nice!

suic on Dec. 16, 2015, 12:22 p.m.
Thanks! :)

elhreno on Sept. 18, 2016, 2:52 p.m.
Really nice. I'm not very familiar with lambdas, so this gave ne a good insight on how I can use them.

Nosveo on Nov. 13, 2016, 10:41 a.m.
Congratulations so much to learn!

Nosveo on Nov. 13, 2016, 10:42 a.m.
Congratulations! I have so much to learn!

suic on Nov. 13, 2016, 10:56 a.m.
I'm glad to hear that :)

Arachnivore on Jan. 3, 2017, 4:58 p.m.
Great use of filter and "falsyness"!

Adam_Navarrete on Feb. 3, 2017, 1:47 a.m.
Bien.

suic on Feb. 3, 2017, 2:48 p.m.
Merci :)

alex.stefanov2 on July 12, 2017, 2:33 p.m.
... I made a super long one-liner. It used two for loops combined with recursion. Took me 3 hours to make and I was super proud of it. Your version just makes me want to both laugh and cry xD

suic on July 12, 2017, 2:51 p.m.
Hi, if you like this solution, feel free to upvote it :) Regards, suic

Carvalho on Nov. 27, 2017, 1:56 p.m.
Congratulations! If you let me, here is another way to write the code snippet above: <pre class='brush: python'>def checkio(data): return [item for item in data if bool(data.count(item) - 1)] </pre>

suic on Nov. 27, 2017, 5:50 p.m.
You're right. Ad your solution: You can omit `bool()`. Regards, suic

Nour on April 15, 2018, 12:39 p.m.
it is nice line of code, but the count will give you o(n*n)

suic on June 18, 2018, 3:42 p.m.
I know, this wasn't meant to be speedy :)

alekseykonotop on Nov. 11, 2018, 11:42 a.m.
Very clear solution.

svalazar on Dec. 23, 2020, 10:23 a.m.
An elegant solution! Bravo!

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