First clear solution for Non-unique Elements by plutasnyy - python coding challenges

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First solution in Clear category for Non-unique Elements by plutasnyy

#Your optional code here
#You can import some modules or create additional functions


def checkio(data):
    i=0
    while i
                        Oct. 16, 2016

                        
                            Comments:
                            
                                
                                    Oleg_Levonjuk
 on Jan. 27, 2021, 11:15 a.m.

                                    <p>Not very pythonic, but pretty clear) Btw, you forgot to remove print^^</p>

                                
                            
                                
                                    rybld2
 on June 7, 2021, 11:11 a.m.

                                    <p>Well
My question was "what about while ?"
When i see : while i<len(data) and  after i +=1
i am not absolutely sure that "while" was indispensable</p>

<p>of course the work is done </p>

                                
                            
                                
                                    gtmizyuk
 on July 15, 2021, 8:26 a.m.

                                    <p>I would use a cycle "for" and pass in a cycle on elements (not on indexes) and would count at once quantity of elements, without addressing elements on indexes. </p>

<p>Also, in my opinion, it is not a very good option to delete items from the list you are going through and determine the length of the list each time. In the condition of the problem it is specified that it is necessary to delete, probably, it has caused to do so in the decision. It would be better, I think, to create a separate list and add non-unique items. </p>

<p>But the decision deserves attention.</p>

                                
                            
                                
                                    mr_vads
 on July 20, 2021, 9:08 p.m.

                                    <p>it works</p>

                                
                            
                                
                                    OGR
 on Sept. 20, 2021, 1:18 p.m.

                                    <p>nice and clear. Btw, you forgot to remove print ;)</p>

                                
                            
                                
                                    darkera
 on Sept. 27, 2021, 3:58 a.m.

                                    <p>[a for a in data if data.count[a]&gt;1]</p>

                                
                            
                                
                                    asjdhjshdajsd
 on Dec. 7, 2021, 3:33 p.m.

                                    <p>Looks good! Though you might want to use list comprehension. </p>

                                
                            
                                
                                    rustamgiz
 on Jan. 28, 2023, 5:52 a.m.

                                    <p>A nice solution in terms of saving the memory needed to run the program. However, from a performance point of view, this will take longer than a program that adds non-unique elements to a new list.</p>

                                
                            
                                
                                    _Jan_
 on Oct. 4, 2024, 2:03 p.m.

                                    <p>It works, but I think while doesn't suit here, and changing intial sequence is not a good idea</p>

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