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First solution in Creative category for Non-unique Elements by olekszymczak
#Your optional code here
#You can import some modules or create additional functions
def uni(lis,x):
suma=0
for i in range(len(lis)):
if lis[i]==x:
suma=suma+1
if suma==1:
return True
else:
return False
def checkio(data: list) -> list:
#Your code here
#It's main function. Don't remove this function
#It's used for auto-testing and must return a result for check.
#replace this for solution
for i in range(len(data)):
for j in range(i,len(data)):
if uni(data,data[i])==True:
data.pop(i)
return data
#Some hints
#You can use list.count(element) method for counting.
#Create new list with non-unique elements
#Loop over original list
if __name__ == "__main__":
#These "asserts" using only for self-checking and not necessary for auto-testing
assert list(checkio([1, 2, 3, 1, 3])) == [1, 3, 1, 3], "1st example"
assert list(checkio([1, 2, 3, 4, 5])) == [], "2nd example"
assert list(checkio([5, 5, 5, 5, 5])) == [5, 5, 5, 5, 5], "3rd example"
assert list(checkio([10, 9, 10, 10, 9, 8])) == [10, 9, 10, 10, 9], "4th example"
print("It is all good. Let's check it now")
Nov. 28, 2018
