My 1st solution! uncategorized solution for Non-unique Elements by aggelgian - python coding challenges

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My 1st solution! solution in Uncategorized category for Non-unique Elements by aggelgian

def checkio(data):
    bucket = {}
    for x in data:
        bucket[x] = bucket[x] + 1 if x in bucket else 1
    return list(filter(lambda x: bucket[x] > 1, data))

Feb. 5, 2014

Comments:

nickie on Feb. 5, 2014, 10:36 p.m.
<p>Line 5 in the Erlang way: :-)</p> <pre class='brush: python'>return list(filter(lambda x: bucket[x] > 1, data)) </pre> <p>The same line, in the Python (and Haskell, BTW) way:</p> <pre class='brush: python'>return [x for x in data if bucket[x] > 1] </pre>

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