Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
First solution in Clear category for Non-unique Elements by PawelMartyniuk
#Your optional code here
#You can import some modules or create additional functions
def checkio(data):
i = len(data)
k = 0
while (i > k and k != len(data) ):
if data.count(data[k]) == 1:
data.remove(data[k])
k = k -1
k = k + 1
return data
#Some hints
#You can use list.count(element) method for counting.
#Create new list with non-unique elements
#Loop over original list
if __name__ == "__main__":
#These "asserts" using only for self-checking and not necessary for auto-testing
assert isinstance(checkio([1]), list), "The result must be a list"
assert checkio([1, 2, 3, 1, 3]) == [1, 3, 1, 3], "1st example"
assert checkio([1, 2, 3, 4, 5]) == [], "2nd example"
assert checkio([5, 5, 5, 5, 5]) == [5, 5, 5, 5, 5], "3rd example"
assert checkio([10, 9, 10, 10, 9, 8]) == [10, 9, 10, 10, 9], "4th example"
Oct. 22, 2016
