Another way creative solution for Non-unique Elements by Merzix - python coding challenges

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Another way solution in Creative category for Non-unique Elements by Merzix

def checkio(data):
    data_source = data.copy()
    unique = set(data)
    for x in unique:
        data.remove(x)
    double = set(data)
    return [x for x in data_source if x in double]

May 30, 2017

Comments:

veky on May 30, 2017, 12:12 p.m.
Interesting approach. I know why it's fast, but I wouldn't believe it's so much faster. It seems we have another "optimization anecdote". ;-)

Merzix on May 31, 2017, 8:28 a.m.
"MOST FASTER" - i meant from the submitted, not 'in the world' :) <ul> <li>tested with <a href="http://rextester.com/TBPP2311">service</a></li> <li>test <a href="http://rextester.com/DVDXJ24654">code</a> by hand</li> </ul> P.S. Sorry, but i don`t understand about "optimization anecdote"

Merzix on May 31, 2017, 9:08 a.m.
You are absolutely right! I had wrong test of my func (thank to <a href="http://www.pythontutor.com/visualize.html">this visualisation service</a>). Sorry. P.S. I renamed solution.

veky on May 31, 2017, 2:59 p.m.
Ah yes, now it's a lot less astonishing. :-) Anyway, this just shows that measuring performance of Python code is something between advanced rocket science and contemporary black magic. :-D (Even BDFL <a href="https://www.python.org/doc/essays/list2str/">gets it wrong</a> at times.;)

radek120299 on Nov. 1, 2018, 10:05 a.m.
nice

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