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First solution in Clear category for Non-unique Elements by Krzysztof__wierblewski
#Your optional code here
#You can import some modules or create additional functions
def checkio(data):
ile = 0
ite = 0
list = []
dl = len(data)
while ite < dl:
ile = data.count(data[ite])
if ile > 1:
list.append(data[ite])
ite+=1
return list
#Some hints
#You can use list.count(element) method for counting.
#Create new list with non-unique elements
#Loop over original list
if __name__ == "__main__":
#These "asserts" using only for self-checking and not necessary for auto-testing
assert isinstance(checkio([1]), list), "The result must be a list"
assert checkio([1, 2, 3, 1, 3]) == [1, 3, 1, 3], "1st example"
assert checkio([1, 2, 3, 4, 5]) == [], "2nd example"
assert checkio([5, 5, 5, 5, 5]) == [5, 5, 5, 5, 5], "3rd example"
assert checkio([10, 9, 10, 10, 9, 8]) == [10, 9, 10, 10, 9], "4th example"
Jan. 10, 2017
