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First solution in Clear category for Non-unique Elements by BeataBaczynska
#Your optional code here
#You can import some modules or create additional functions
def checkio(data):
#Your code here
#It's main function. Don't remove this function
#It's used for auto-testing and must return a result for check.
NewArray = []
i = 0
while i < len(data):
x = data[i]
ile = data.count(x)
if ile > 1 :
NewArray.append(x)
i = i + 1
else:
i = i + 1
return NewArray
#replace this for solution
return data
#Some hints
#You can use list.count(element) method for counting.
#Create new list with non-unique elements
#Loop over original list
if __name__ == "__main__":
#These "asserts" using only for self-checking and not necessary for auto-testing
assert list(checkio([1, 2, 3, 1, 3])) == [1, 3, 1, 3], "1st example"
assert list(checkio([1, 2, 3, 4, 5])) == [], "2nd example"
assert list(checkio([5, 5, 5, 5, 5])) == [5, 5, 5, 5, 5], "3rd example"
assert list(checkio([10, 9, 10, 10, 9, 8])) == [10, 9, 10, 10, 9], "4th example"
print("It is all good. Let's check it now")
Oct. 15, 2017
