Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
First solution in Clear category for Non-unique Elements by AlexPro
def checkio(data):
x = data[:]
for r in data:
if data.count(r) == 1:
x.remove(r)
return x
# Some hints
# You can use list.count(element) method for counting.
# Create new list with non-unique elements
# Loop over original list
if __name__ == "__main__":
#These "asserts" using only for self-checking and not necessary for auto-testing
assert isinstance(checkio([1]), list), "The result must be a list"
assert checkio([1, 2, 3, 1, 3]) == [1, 3, 1, 3], "1st example"
assert checkio([1, 2, 3, 4, 5]) == [], "2nd example"
assert checkio([5, 5, 5, 5, 5]) == [5, 5, 5, 5, 5], "3rd example"
assert checkio([10, 9, 10, 10, 9, 8]) == [10, 9, 10, 10, 9], "4th example"
Jan. 26, 2016
