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First solution in Clear category for Non-unique Elements by Adrian_W
#Your optional code here
#You can import some modules or create additional functions
def checkio(data):
temp = list()
for x in range(0, len(data)):
if data.count(data[x])==1:
temp.append(data[x])
while len(temp):
data.remove(temp[0])
temp.remove(temp[0])
#Your code here
#It's main function. Don't remove this function
#It's used for auto-testing and must return a result for check.
#replace this for solution
return data
#Some hints
#You can use list.count(element) method for counting.
#Create new list with non-unique elements
#Loop over original list
if __name__ == "__main__":
#These "asserts" using only for self-checking and not necessary for auto-testing
assert isinstance(checkio([1]), list), "The result must be a list"
assert checkio([1, 2, 3, 1, 3]) == [1, 3, 1, 3], "1st example"
assert checkio([1, 2, 3, 4, 5]) == [], "2nd example"
assert checkio([5, 5, 5, 5, 5]) == [5, 5, 5, 5, 5], "3rd example"
assert checkio([10, 9, 10, 10, 9, 8]) == [10, 9, 10, 10, 9], "4th example"
Oct. 7, 2016
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