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First solution in Clear category for Multiplication Table by yukirin
from operator import or_, and_, xor
def checkio(first, second, result=0):
first = [int(c) for c in bin(first)[2:]]
second = [int(c) for c in bin(second)[2:]]
for ope in and_, or_, xor:
result += sum(int(''.join(str(ope(x, y)) for y in second), 2) for x in first)
return result
if __name__ == '__main__':
assert checkio(4, 6) == 38
assert checkio(2, 7) == 28
assert checkio(7, 2) == 18
April 10, 2015
