First clear solution for Multiplication Table by tihenko - python coding challenges

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First solution in Clear category for Multiplication Table by tihenko

def checkio(first, second):
    answer=0
    line1=line2=line3=''
    for f in bin(first)[2:]:
        for s in bin(second)[2:]:
            line1+=str(int(f)&int(s))  #and
            line2+=str(int(f)|int(s))  #or
            line3+=str(int(f)^int(s))  #xor
        answer+=int(line1, 2)+int(line2, 2)+int(line3, 2)
        line1=line2=line3=''
    return answer

Feb. 28, 2014

Comments:

Cjkjvfnby on June 10, 2014, 9:57 p.m.
You code "init lines" twice (lien3, line10) before all work and after inner cycle. You can do it just once before inner cycle. You can convert first and second to list of ints, and not call int in inner cycle.

tihenko on June 10, 2014, 11:01 p.m.
<pre class='brush: python'>def checkio(first, second): answer=0 for f in bin(first)[2:]: line1=line2=line3='' f=int(f) for s in bin(second)[2:]: s=int(s) line1+=str(f&s) #and line2+=str(f|s) #or line3+=str(f^s) #xor answer+=int(line1, 2)+int(line2, 2)+int(line3, 2) return answer </pre>

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