1pass clear solution for The Most Wanted Letter by veky - python coding challenges

Enable Javascript in your browser and then refresh this page, for a much enhanced experience.

1pass solution in Clear category for The Most Wanted Letter by veky

def checkio(text):
    import collections
    freqs = collections.Counter(filter(str.isalpha, text.lower()))
    mode = max(freqs.values())
    return min(letter for letter, freq in freqs.items() if freq == mode)

May 5, 2016

Comments:

Gabbek on May 15, 2016, 11:07 a.m.
I might not be a person who comments often, but I'm hoping to change it. Thanks for all wonderful solutions, I'm learning a lot from them! :)

veky on May 17, 2016, 6:29 a.m.
Thank you for all the future comments. ;-)

thatkyle on Nov. 20, 2017, 4:22 a.m.
I'm really glad you posted this solution. I have just started using collections and this is really helpful for understanding the basics of collections and dictionaries in general. Thanks!

veky on Nov. 20, 2017, 5:53 a.m.
No problem. It was my pleasure. :-)

william60712 on Aug. 20, 2019, 8:39 a.m.
Use sorted(text.lower()) and return freqs.most_common()[0][0] may make it more clear.

veky on Aug. 20, 2019, 8:44 a.m.
It is a sign of great progress when people value clarity to the extent of prefering a total sort instead of selecting just the maximum. :-D About most_common: I'd agree if it had a reasonable API. Double zero indexing I don't find reasonable. :-P

bsquare on Sept. 18, 2019, 10:24 a.m.
This one if very very clear :)

veky on Sept. 18, 2019, 10:50 a.m.
Discuss it with the post above. B-)

Strings and Integers

0 %

You ClassRoom Demo is Ready With the new tool CheckiO ClassRoom, you will be able to analyze your students' progress, have your own leaderboard, change missions order on the map, and so on.