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sorted(Counter) solution in Clear category for The Most Wanted Letter by mreinhardt
from collections import Counter
import string
def checkio(text):
count = Counter([c.lower() for c in text if c in string.ascii_letters])
count = sorted(count.items(), key=lambda t: t[0]) # alphabetize
return sorted(count, key=lambda t: t[1], reverse=True)[0][0]
June 4, 2015
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