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First solution in Uncategorized category for The Most Wanted Letter by mkobylka
bukvi = 'abcdefghijklmnopqrstuvwxyz'
def remove_other(text):
text = text.lower()
non_special_simbols=[i for i in text if i.isalpha()==True]
text = list(set(bukvi).intersection(text))
return [''.join(text),''.join(non_special_simbols)]
def checkio(text):
text = remove_other(text)
v=[]
bukvi1=list(bukvi)
b={}.fromkeys(text[0],0)
for i in text[1]:
b[i]=text[1].count(i)
for key in b:
if b[key] == max(b.values()):
v.append(bukvi1.index(key))
return bukvi1[min(v)]
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio("Hello World!") == "l", "Hello test"
assert checkio("How do you do?") == "o", "O is most wanted"
assert checkio("One") == "e", "All letter only once."
assert checkio("Oops!") == "o", "Don't forget about lower case."
assert checkio("AAaooo!!!!") == "a", "Only letters."
assert checkio("abe") == "a", "The First."
print("Start the long test")
assert checkio("a" * 9000 + "b" * 1000) == "a", "Long."
print("The local tests are done.")
Dec. 17, 2015
