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Dictionary comprehension solution in Speedy category for The Most Wanted Letter by makernaren
# migrated from python 2.7
import re
def checkio(text):
# detailed
# text = re.sub('[^A-Za-z]+', '', text).lower()
# d = {x:text.count(x) for x in text}
# occurance = max(sorted(d.items()), key=lambda x: x[1])[0]
# return occurance
# messy
text = re.sub('[^A-Za-z]+', '', text).lower()
return max(sorted({x:text.count(x) for x in text}.items()),key=lambda x: x[1])[0]
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio("Hello World!") == "l", "Hello test"
assert checkio("How do you do?") == "o", "O is most wanted"
assert checkio("One") == "e", "All letter only once."
assert checkio("Oops!") == "o", "Don't forget about lower case."
assert checkio("AAaooo!!!!") == "a", "Only letters."
assert checkio("abe") == "a", "The First."
print("Start the long test")
assert checkio("a" * 9000 + "b" * 1000) == "a", "Long."
print("The local tests are done.")
Jan. 14, 2015
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