dict + lambda clear solution for The Most Wanted Letter by kdim - python coding challenges

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dict + lambda solution in Clear category for The Most Wanted Letter by kdim

def checkio(text: str) -> str:
    t = text.lower()
    d = {i: t.count(i) for i in t if 'a' <= i <= 'z'}
    return sorted(d.items(), key=lambda x: (-x[1], x[0]))[0][0]

Jan. 28, 2021

Comments:

H0r4c3 on Sept. 21, 2022, 6:58 p.m.
Interesting use of lambda!

CDG.Axel on March 18, 2023, 11:59 p.m.
Love tuple sorting! Btw I can't stop myself with useless advices :) <ol> <li>What's the reason of dict using?</li> <li>Looks like filter simpler than if</li> <li>Why sorted instead of min? <pre class='brush: python'>t = text.lower() d = [(i, t.count(i)) for i in filter(str.isalpha, t)] # list of tuple + filter return min(d, key=lambda x: (-x[1], x[0]))[0] # min instead of sorted </pre></li> </ol> PS: if you hate redundant calculation: <pre class='brush: python'>t = text.lower() return min([(i, t.count(i)) for i in map(chr, range(97, 123))], key=lambda x: (-x[1], x[0]))[0] </pre>

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