The most wanted letter clear solution for The Most Wanted Letter by imcapableofanything - python coding challenges

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The most wanted letter solution in Clear category for The Most Wanted Letter by imcapableofanything

import re
def checkio(text):
    chars = "".join(re.findall("[a-zA-Z]+", text.lower()))        
    data = {}    
    for ch in chars:
        if not ch in data:
            data[ch] = 1
        else:
            data[ch] += 1
    sorted_data = sorted(data.items(), key=lambda x: (-x[1], x[0]))      
    for item in sorted_data:
        return item[0]

Nov. 12, 2015

Comments:

larmalade on Nov. 23, 2015, 4:23 a.m.
Is this solution checked? Why not get rid of line 11? The for loop is only going to run once!

imcapableofanything on Dec. 1, 2015, 7:09 a.m.
Yeah the solution was checked. You can't post it here if it's not checked. But still: Just checked this -> return sorted_data[0][0] And it works fine as well. So yeah it seems there's no need in that "for" line. Thank you for the tip!

Strings and Integers

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