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with collections.Counter() solution in Clear category for The Most Wanted Letter by busiaaq
import collections
def checkio(text: str) -> str:
sorted_text = text.lower()
sorted_text = sorted(sorted_text)
c = collections.Counter()
for x in sorted_text:
if x.isalpha():
c[x] += 1
return c.most_common(1)[0][0]
if __name__ == '__main__':
print("Example:")
print(checkio("Hello World!"))
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio("Hello World!") == "l", "Hello test"
assert checkio("How do you do?") == "o", "O is most wanted"
assert checkio("One") == "e", "All letter only once."
assert checkio("Oops!") == "o", "Don't forget about lower case."
assert checkio("AAaooo!!!!") == "a", "Only letters."
assert checkio("abe") == "a", "The First."
print("Start the long test")
assert checkio("a" * 9000 + "b" * 1000) == "a", "Long."
print("The local tests are done.")
June 20, 2019
