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My first solution in Clear category for The Most Wanted Letter by VladislavAksiotis
def checkio(row):
dic = {}
lis = []
row = row.lower()
for lt in row:
if lt.isalpha():
dic[lt] = row.count(lt)
m = max(dic.values())
for k, v in dic.items():
if v == m:
lis.append(k)
return min(lis)
Jan. 30, 2020
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