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Beginner's Solution solution in Clear category for The Most Wanted Letter by Selindian
def checkio(text: str) -> str:
#replace this for solution
dictionary = {} # Create empty dict.
for letter in range(97,123): dictionary[chr(letter)] = 0 # Create all keys a==chr(97) - z==chr(122) for the dict. Note that range exclude the end.
for character in text.lower(): # Loop through the lowered text
if character in dictionary: dictionary[character] += 1 # If the current character is in dict then increase the number of the corresponding key by one.
return max(dictionary, key=dictionary.get) # max in combination with key=dictionary.get gets the first key with the highest int.
if __name__ == '__main__':
print("Example:")
print(checkio("Hello World!"))
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio("Hello World!") == "l", "Hello test"
assert checkio("How do you do?") == "o", "O is most wanted"
assert checkio("One") == "e", "All letter only once."
assert checkio("Oops!") == "o", "Don't forget about lower case."
assert checkio("AAaooo!!!!") == "a", "Only letters."
assert checkio("abe") == "a", "The First."
print("Start the long test")
assert checkio("a" * 9000 + "b" * 1000) == "a", "Long."
print("The local tests are done.")
Feb. 24, 2022
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